What is (3-2x)/5 <4<= (1-x)/2 ?

The solution to (3-2x)/5 <4<= (1-x)/2 is -17/2 <x<=-7

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(3-2x)/5 <4<= (1-x)/2

\frac{3 - 2 x}{5} < 4 \leq \frac{1 - x}{2}

- \frac{17}{2} < x \leq - 7

Interval Notation

(- \frac{17}{2}, - 7]

Decimal Notation

- 8.5 < x \leq - 7

Solution steps

\frac{3 - 2 x}{5} < 4 \leq \frac{1 - x}{2}

a < u \leq b

then

a < u and u \leq b

\frac{3 - 2 x}{5} < 4 and 4 \leq \frac{1 - x}{2}

\frac{3 - 2 x}{5} < 4 : x > - \frac{17}{2}

4 \leq \frac{1 - x}{2} : x \leq - 7

Combine the intervals

x > - \frac{17}{2} and x \leq - 7

Merge Overlapping Intervals

- \frac{17}{2} < x \leq - 7

\frac{0.5 ( 9.1 - 7.3 ) ^{2}}{5.8 + 8.6 - 5.4}

5 - b = 1

5^{n} - 5^{n - 3}

\frac{3 ( x - 4 )}{2} \geq \frac{2 x}{5} - 9

i^{43}

What is (3-2x)/5 <4<= (1-x)/2 ?
The solution to (3-2x)/5 <4<= (1-x)/2 is -17/2 <x<=-7