What are the solutions to the equation x(2x-5)=12 ?

The solutions to the equation x(2x-5)=12 are x=4,x=-3/2

Find the zeros of x(2x-5)=12

The zeros of x(2x-5)=12 are x=4,x=-3/2

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x (2 x - 5) = 12

x = 4, x = - \frac{3}{2}

Decimal Notation

x = 4, x = - 1.5

Solution steps

x (2 x - 5) = 12

Expand

x (2 x - 5) : 2 x^{2} - 5 x

2 x^{2} - 5 x = 12

Move

12

to the left side

2 x^{2} - 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 12) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 2}

x = \frac{- ( - 5 ) + 11}{2 \cdot 2} : 4

x = \frac{- ( - 5 ) - 11}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 4, x = - \frac{3}{2}

x^{\frac{7}{2}} - x^{\frac{3}{2}}

5 ∣ x - 3 ∣ > 15

5 b - 4 = 6 (b + 2)

13 = \frac{8}{9} y - (- 5)

- 7 - (- 3)

What are the solutions to the equation x(2x-5)=12 ?
The solutions to the equation x(2x-5)=12 are x=4,x=-3/2
Find the zeros of x(2x-5)=12
The zeros of x(2x-5)=12 are x=4,x=-3/2