What are the solutions to the equation 4x^2-9x+17=-4x+8 ?

The solutions to the equation 4x^2-9x+17=-4x+8 are x= 5/8+i(sqrt(119))/8 ,x= 5/8-i(sqrt(119))/8

Find the zeros of 4x^2-9x+17=-4x+8

The zeros of 4x^2-9x+17=-4x+8 are x= 5/8+i(sqrt(119))/8 ,x= 5/8-i(sqrt(119))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 9 x + 17 = - 4 x + 8

x = \frac{5}{8} + i \frac{119}{8}, x = \frac{5}{8} - i \frac{119}{8}

Solution steps

4 x^{2} - 9 x + 17 = - 4 x + 8

Move

8

to the left side

4 x^{2} - 9 x + 9 = - 4 x

Move

4 x

to the left side

4 x^{2} - 5 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

Simplify

(- 5)^{2} - 4 \cdot 4 \cdot 9 : 119 i

x_{1, 2} = \frac{- ( - 5 ) \pm 119 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 119 i}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 119 i}{2 \cdot 4}

x = \frac{- ( - 5 ) + 119 i}{2 \cdot 4} : \frac{5}{8} + i \frac{119}{8}

x = \frac{- ( - 5 ) - 119 i}{2 \cdot 4} : \frac{5}{8} - i \frac{119}{8}

The solutions to the quadratic equation are:

x = \frac{5}{8} + i \frac{119}{8}, x = \frac{5}{8} - i \frac{119}{8}

4 y^{2} - 8 y - 5

(x - 4) = 6

2 x^{2} - \frac{11}{2} x - \frac{3}{2} = 0

\frac{π}{8} + \frac{π}{8}

4^{{\frac{5}{2}}}

What are the solutions to the equation 4x^2-9x+17=-4x+8 ?
The solutions to the equation 4x^2-9x+17=-4x+8 are x= 5/8+i(sqrt(119))/8 ,x= 5/8-i(sqrt(119))/8
Find the zeros of 4x^2-9x+17=-4x+8
The zeros of 4x^2-9x+17=-4x+8 are x= 5/8+i(sqrt(119))/8 ,x= 5/8-i(sqrt(119))/8