What are the solutions to the equation 3x^2-2x(x-4)=x-12 ?

The solutions to the equation 3x^2-2x(x-4)=x-12 are x=-3,x=-4

Find the zeros of 3x^2-2x(x-4)=x-12

The zeros of 3x^2-2x(x-4)=x-12 are x=-3,x=-4

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3 x^{2} - 2 x (x - 4) = x - 12

x = - 3, x = - 4

Solution steps

3 x^{2} - 2 x (x - 4) = x - 12

Expand

3 x^{2} - 2 x (x - 4) : x^{2} + 8 x

x^{2} + 8 x = x - 12

Move

12

to the left side

x^{2} + 8 x + 12 = x

Move

x

to the left side

x^{2} + 7 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 1}, x_{2} = \frac{- 7 - 1}{2 \cdot 1}

x = \frac{- 7 + 1}{2 \cdot 1} : - 3

x = \frac{- 7 - 1}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 3, x = - 4

8 x - 48 = 6 x + 32

0. 9^{3}

\frac{2 π}{\frac{π}{5}}

337 5^{\frac{1}{3}}

\frac{10 + 5 i}{2 - i}

What are the solutions to the equation 3x^2-2x(x-4)=x-12 ?
The solutions to the equation 3x^2-2x(x-4)=x-12 are x=-3,x=-4
Find the zeros of 3x^2-2x(x-4)=x-12
The zeros of 3x^2-2x(x-4)=x-12 are x=-3,x=-4