What are the solutions to the equation 12x^2+82x=14 ?

The solutions to the equation 12x^2+82x=14 are x= 1/6 ,x=-7

Find the zeros of 12x^2+82x=14

The zeros of 12x^2+82x=14 are x= 1/6 ,x=-7

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12 x^{2} + 82 x = 14

x = \frac{1}{6}, x = - 7

Decimal Notation

x = 0.16666 \dots, x = - 7

Solution steps

12 x^{2} + 82 x = 14

Move

14

to the left side

12 x^{2} + 82 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 82 \pm 8 2 ^{2} - 4 \cdot 12 ( - 14 )}{2 \cdot 12}

8 2^{2} - 4 \cdot 12 (- 14) = 86

x_{1, 2} = \frac{- 82 \pm 86}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 82 + 86}{2 \cdot 12}, x_{2} = \frac{- 82 - 86}{2 \cdot 12}

x = \frac{- 82 + 86}{2 \cdot 12} : \frac{1}{6}

x = \frac{- 82 - 86}{2 \cdot 12} : - 7

The solutions to the quadratic equation are:

x = \frac{1}{6}, x = - 7

\frac{18}{6}

4 x^{2} - 56 x + 268 = 0

65 = \frac{3}{4} x - 7

\frac{1}{6} + \frac{1}{4}

0.59 = - 0.2746 x^{2} + 1.0052 x + 0.2694

What are the solutions to the equation 12x^2+82x=14 ?
The solutions to the equation 12x^2+82x=14 are x= 1/6 ,x=-7
Find the zeros of 12x^2+82x=14
The zeros of 12x^2+82x=14 are x= 1/6 ,x=-7