What are the solutions to the equation x^2-8x-3=0 ?

The solutions to the equation x^2-8x-3=0 are x=4+sqrt(19),x=4-sqrt(19)

Find the zeros of x^2-8x-3=0

The zeros of x^2-8x-3=0 are x=4+sqrt(19),x=4-sqrt(19)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 8 x - 3 = 0

x = 4 + 19, x = 4 - 19

Decimal Notation

x = 8.35889 \dots, x = - 0.35889 \dots

Solution steps

x^{2} - 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 3) = 219

x_{1, 2} = \frac{- ( - 8 ) \pm 2 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 19}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 19}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 19}{2 \cdot 1} : 4 + 19

x = \frac{- ( - 8 ) - 2 19}{2 \cdot 1} : 4 - 19

The solutions to the quadratic equation are:

x = 4 + 19, x = 4 - 19

(12 x - y)^{2} - (4 x - 3 y)^{2}

7 x - 21 = x + 15

- \frac{3}{4} x < - 9

x^{3} - x^{2} - 37 x - 35

t^{2} - 10 t + 25

What are the solutions to the equation x^2-8x-3=0 ?
The solutions to the equation x^2-8x-3=0 are x=4+sqrt(19),x=4-sqrt(19)
Find the zeros of x^2-8x-3=0
The zeros of x^2-8x-3=0 are x=4+sqrt(19),x=4-sqrt(19)