What are the solutions to the equation m^2=m+20 ?

The solutions to the equation m^2=m+20 are m=5,m=-4

Find the zeros of m^2=m+20

The zeros of m^2=m+20 are m=5,m=-4

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m^{2} = m + 20

m = 5, m = - 4

Solution steps

m^{2} = m + 20

Move

20

to the left side

m^{2} - 20 = m

Move

m

to the left side

m^{2} - 20 - m = 0

Write in the standard form

a x^{2} + b x + c = 0

m^{2} - m - 20 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

m_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

m = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

m = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

m = 5, m = - 4

\frac{5}{3} (- \frac{3}{4} + \frac{1}{2})

- r + 9 \leq 2

\frac{5}{6} (12 m - 18) < - 25

(3 x)^{\frac{1}{3}}

What are the solutions to the equation m^2=m+20 ?
The solutions to the equation m^2=m+20 are m=5,m=-4
Find the zeros of m^2=m+20
The zeros of m^2=m+20 are m=5,m=-4