What are the solutions to the equation x^2+3x-12=6 ?

The solutions to the equation x^2+3x-12=6 are x=3,x=-6

Find the zeros of x^2+3x-12=6

The zeros of x^2+3x-12=6 are x=3,x=-6

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x^{2} + 3 x - 12 = 6

x = 3, x = - 6

Solution steps

x^{2} + 3 x - 12 = 6

Move

6

to the left side

x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 \cdot 1}, x_{2} = \frac{- 3 - 9}{2 \cdot 1}

x = \frac{- 3 + 9}{2 \cdot 1} : 3

x = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 3, x = - 6

8 x^{2} - 10 x + 3 = 0

3 (a - 6) < 4 + a

5 x + 3 = - 4 (1 - x)

119 < 8 + 3 (2 - 5 x)

\frac{7}{2} + 3

What are the solutions to the equation x^2+3x-12=6 ?
The solutions to the equation x^2+3x-12=6 are x=3,x=-6
Find the zeros of x^2+3x-12=6
The zeros of x^2+3x-12=6 are x=3,x=-6