What are the solutions to the equation -0.1x^2+1.2x+6=0 ?

The solutions to the equation -0.1x^2+1.2x+6=0 are x=-2(2sqrt(6)-3),x=2(3+2sqrt(6))

Find the zeros of -0.1x^2+1.2x+6=0

The zeros of -0.1x^2+1.2x+6=0 are x=-2(2sqrt(6)-3),x=2(3+2sqrt(6))

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- 0.1 x^{2} + 1.2 x + 6 = 0

x = - 2 (26 - 3), x = 2 (3 + 26)

Decimal Notation

x = - 3.79795 \dots, x = 15.79795 \dots

Solution steps

- 0.1 x^{2} + 1.2 x + 6 = 0

Multiply both sides by

10

- x^{2} + 12 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 1 ) \cdot 60}{2 ( - 1 )}

1 2^{2} - 4 (- 1) \cdot 60 = 86

x_{1, 2} = \frac{- 12 \pm 8 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 12 + 8 6}{2 ( - 1 )}, x_{2} = \frac{- 12 - 8 6}{2 ( - 1 )}

x = \frac{- 12 + 8 6}{2 ( - 1 )} : - 2 (26 - 3)

x = \frac{- 12 - 8 6}{2 ( - 1 )} : 2 (3 + 26)

The solutions to the quadratic equation are:

x = - 2 (26 - 3), x = 2 (3 + 26)

0 = \frac{1}{3} t^{2} - 6 t + 100

rs + 4 s t

2 x ln (x) + x > 0

3 x (x - 2) > 1 - 7 x - 3 x^{2}

\frac{x + 2}{15} - \frac{x - 3}{5} = \frac{2}{3}

What are the solutions to the equation -0.1x^2+1.2x+6=0 ?
The solutions to the equation -0.1x^2+1.2x+6=0 are x=-2(2sqrt(6)-3),x=2(3+2sqrt(6))
Find the zeros of -0.1x^2+1.2x+6=0
The zeros of -0.1x^2+1.2x+6=0 are x=-2(2sqrt(6)-3),x=2(3+2sqrt(6))