What are the solutions to the equation 9x^2=10x+2 ?

The solutions to the equation 9x^2=10x+2 are x=(5+sqrt(43))/9 ,x=(5-sqrt(43))/9

Find the zeros of 9x^2=10x+2

The zeros of 9x^2=10x+2 are x=(5+sqrt(43))/9 ,x=(5-sqrt(43))/9

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9 x^{2} = 10 x + 2

x = \frac{5 + 43}{9}, x = \frac{5 - 43}{9}

Decimal Notation

x = 1.28415 \dots, x = - 0.17304 \dots

Solution steps

9 x^{2} = 10 x + 2

Move

2

to the left side

9 x^{2} - 2 = 10 x

Move

10 x

to the left side

9 x^{2} - 2 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 10 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

(- 10)^{2} - 4 \cdot 9 (- 2) = 243

x_{1, 2} = \frac{- ( - 10 ) \pm 2 43}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 43}{2 \cdot 9}, x_{2} = \frac{- ( - 10 ) - 2 43}{2 \cdot 9}

x = \frac{- ( - 10 ) + 2 43}{2 \cdot 9} : \frac{5 + 43}{9}

x = \frac{- ( - 10 ) - 2 43}{2 \cdot 9} : \frac{5 - 43}{9}

The solutions to the quadratic equation are:

x = \frac{5 + 43}{9}, x = \frac{5 - 43}{9}

3 x^{2} - 2 = 0

24 - 3 x = - 6 x + 22

1 x - 8 = - 3

4 x - 2 < 12

∣ 8 m - 10 ∣ - 9 = 1

What are the solutions to the equation 9x^2=10x+2 ?
The solutions to the equation 9x^2=10x+2 are x=(5+sqrt(43))/9 ,x=(5-sqrt(43))/9
Find the zeros of 9x^2=10x+2
The zeros of 9x^2=10x+2 are x=(5+sqrt(43))/9 ,x=(5-sqrt(43))/9