What is (7n)/(n+1)+8/(n-7) ?

The solution to (7n)/(n+1)+8/(n-7) is (7n^2-41n+8)/((n+1)(n-7))

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simplify (7n)/(n+1)+8/(n-7)

simplify

\frac{7 n}{n + 1} + \frac{8}{n - 7}

\frac{7 n ^{2} - 41 n + 8}{( n + 1 ) ( n - 7 )}

Solution steps

\frac{7 n}{n + 1} + \frac{8}{n - 7}

Least Common Multiplier of

n + 1, n - 7 : (n + 1) (n - 7)

Adjust Fractions based on the LCM

= \frac{7 n ( n - 7 )}{( n + 1 ) ( n - 7 )} + \frac{8 ( n + 1 )}{( n + 1 ) ( n - 7 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{7 n ( n - 7 ) + 8 ( n + 1 )}{( n + 1 ) ( n - 7 )}

Simplify

7 n (n - 7) + 8 (n + 1) : 7 n^{2} - 41 n + 8

= \frac{7 n ^{2} - 41 n + 8}{( n + 1 ) ( n - 7 )}

27 y^{3} + 8

10 x^{2} + 11 x - 6

2 - - 2

- \frac{24}{8}

- 7 - 6 g = - 5 - 4 g

What is (7n)/(n+1)+8/(n-7) ?
The solution to (7n)/(n+1)+8/(n-7) is (7n^2-41n+8)/((n+1)(n-7))