What are the solutions to the equation -2x^2+17=8x-1 ?

The solutions to the equation -2x^2+17=8x-1 are x=-2-sqrt(13),x=sqrt(13)-2

Find the zeros of -2x^2+17=8x-1

The zeros of -2x^2+17=8x-1 are x=-2-sqrt(13),x=sqrt(13)-2

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- 2 x^{2} + 17 = 8 x - 1

x = - 2 - 13, x = 13 - 2

Decimal Notation

x = - 5.60555 \dots, x = 1.60555 \dots

Solution steps

- 2 x^{2} + 17 = 8 x - 1

Move

1

to the left side

- 2 x^{2} + 18 = 8 x

Move

8 x

to the left side

- 2 x^{2} + 18 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} - 8 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 2 ) \cdot 18}{2 ( - 2 )}

(- 8)^{2} - 4 (- 2) \cdot 18 = 413

x_{1, 2} = \frac{- ( - 8 ) \pm 4 13}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 13}{2 ( - 2 )}, x_{2} = \frac{- ( - 8 ) - 4 13}{2 ( - 2 )}

x = \frac{- ( - 8 ) + 4 13}{2 ( - 2 )} : - 2 - 13

x = \frac{- ( - 8 ) - 4 13}{2 ( - 2 )} : 13 - 2

The solutions to the quadratic equation are:

x = - 2 - 13, x = 13 - 2

x^{3} \cdot x^{5}

\frac{0.022 ( 0.0016 ) ^{2}}{2}

12 m^{2} n + 24 m^{3} n^{2} - 36 m^{4} n + 48 m^{5} n^{4}

x^{2} = 8 x - 9

m^{2} + 14 m n^{2} + 49 n^{4}

What are the solutions to the equation -2x^2+17=8x-1 ?
The solutions to the equation -2x^2+17=8x-1 are x=-2-sqrt(13),x=sqrt(13)-2
Find the zeros of -2x^2+17=8x-1
The zeros of -2x^2+17=8x-1 are x=-2-sqrt(13),x=sqrt(13)-2