What are the solutions to the equation 5p(p-2)=0 ?

The solutions to the equation 5p(p-2)=0 are p=0,p=2

Find the zeros of 5p(p-2)=0

The zeros of 5p(p-2)=0 are p=0,p=2

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5 p (p - 2) = 0

p = 0, p = 2

Solution steps

5 p (p - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

p = 0 or p - 2 = 0

Solve

p - 2 = 0 : p = 2

The solutions to the quadratic equation are:

p = 0, p = 2

(- 32)^{\frac{4}{5}}

\frac{3 - i}{2 - i}

t^{2} + 4 t + 4 = 0

9 (x + \frac{1}{7}) = 18

(2 - x) (2 - x)

What are the solutions to the equation 5p(p-2)=0 ?
The solutions to the equation 5p(p-2)=0 are p=0,p=2
Find the zeros of 5p(p-2)=0
The zeros of 5p(p-2)=0 are p=0,p=2