What are the solutions to the equation x^2+3x=18 ?

The solutions to the equation x^2+3x=18 are x=3,x=-6

Find the zeros of x^2+3x=18

The zeros of x^2+3x=18 are x=3,x=-6

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x^{2} + 3 x = 18

x = 3, x = - 6

Solution steps

x^{2} + 3 x = 18

Move

18

to the left side

x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 \cdot 1}, x_{2} = \frac{- 3 - 9}{2 \cdot 1}

x = \frac{- 3 + 9}{2 \cdot 1} : 3

x = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 3, x = - 6

4 y^{2} + 16 y + 15

3 = \frac{( d - 66 )}{7}

(5 + 4 i) (5 - 4 i)

6 x - 5 - x < 0

(x - 0.2)^{2} (x - 0.4)^{2}

What are the solutions to the equation x^2+3x=18 ?
The solutions to the equation x^2+3x=18 are x=3,x=-6
Find the zeros of x^2+3x=18
The zeros of x^2+3x=18 are x=3,x=-6