What is (4k^2+8k+2)-(2k+3) ?

The solution to (4k^2+8k+2)-(2k+3) is 4k^2+6k-1

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simplify (4k^2+8k+2)-(2k+3)

simplify

(4 k^{2} + 8 k + 2) - (2 k + 3)

4 k^{2} + 6 k - 1

Solution steps

(4 k^{2} + 8 k + 2) - (2 k + 3)

Apply rule:

(a) = a

(4 k^{2} + 8 k + 2) = 4 k^{2} + 8 k + 2

= 4 k^{2} + 8 k + 2 - (2 k + 3)

Apply the distributive law:

- (a + b) = - a - b

- (2 k + 3) = - 2 k - 3

= 4 k^{2} + 8 k + 2 - 2 k - 3

Group like terms

= 4 k^{2} + 8 k - 2 k + 2 - 3

Add similar elements:

8 k - 2 k = 6 k

= 4 k^{2} + 6 k + 2 - 3

Subtract the numbers:

2 - 3 = - 1

= 4 k^{2} + 6 k - 1

\frac{1}{12} + \frac{1}{3}

- 9 + 9

6 < \frac{w}{6}

- 7 < x \leq - 6