What are the solutions to the equation 4t^2+9=15t ?

The solutions to the equation 4t^2+9=15t are t=3,t= 3/4

Find the zeros of 4t^2+9=15t

The zeros of 4t^2+9=15t are t=3,t= 3/4

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4 t^{2} + 9 = 15 t

t = 3, t = \frac{3}{4}

Decimal Notation

t = 3, t = 0.75

Solution steps

4 t^{2} + 9 = 15 t

Move

15 t

to the left side

4 t^{2} + 9 - 15 t = 0

Write in the standard form

a x^{2} + b x + c = 0

4 t^{2} - 15 t + 9 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 15)^{2} - 4 \cdot 4 \cdot 9 = 9

t_{1, 2} = \frac{- ( - 15 ) \pm 9}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- ( - 15 ) + 9}{2 \cdot 4}, t_{2} = \frac{- ( - 15 ) - 9}{2 \cdot 4}

t = \frac{- ( - 15 ) + 9}{2 \cdot 4} : 3

t = \frac{- ( - 15 ) - 9}{2 \cdot 4} : \frac{3}{4}

The solutions to the quadratic equation are:

t = 3, t = \frac{3}{4}

z^{2} + \frac{1}{2} z + \frac{1}{4} = 0

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What are the solutions to the equation 4t^2+9=15t ?
The solutions to the equation 4t^2+9=15t are t=3,t= 3/4
Find the zeros of 4t^2+9=15t
The zeros of 4t^2+9=15t are t=3,t= 3/4