What is factor 2n^2-3n-9 ?

The solution to factor 2n^2-3n-9 is (2n+3)(n-3)

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factor 2n^2-3n-9

factor

2 n^{2} - 3 n - 9

(2 n + 3) (n - 3)

Solution steps

2 n^{2} - 3 n - 9

Break the expression into groups

= (2 n^{2} + 3 n) + (- 6 n - 9)

Factor out

n

from

2 n^{2} + 3 n : n (2 n + 3)

Factor out

- 3

from

- 6 n - 9 : - 3 (2 n + 3)

= n (2 n + 3) - 3 (2 n + 3)

Factor out common term

2 n + 3

= (2 n + 3) (n - 3)

- 6 v u^{2} - u v^{2} - 22 u^{2} v^{2}

16 x^{2} + 6 x - 110 = 0

9 n^{4} - 18 n^{3} + 27 n^{2}

∣ x + 8 ∣ + 8 \geq 4

∣ x - 3 ∣ + 4 \leq 6