What are the solutions to the equation c^2+8c=-2 ?

The solutions to the equation c^2+8c=-2 are c=-4+sqrt(14),c=-4-sqrt(14)

Find the zeros of c^2+8c=-2

The zeros of c^2+8c=-2 are c=-4+sqrt(14),c=-4-sqrt(14)

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c^{2} + 8 c = - 2

c = - 4 + 14, c = - 4 - 14

Decimal Notation

c = - 0.25834 \dots, c = - 7.74165 \dots

Solution steps

c^{2} + 8 c = - 2

Move

2

to the left side

c^{2} + 8 c + 2 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 2 = 214

c_{1, 2} = \frac{- 8 \pm 2 14}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 8 + 2 14}{2 \cdot 1}, c_{2} = \frac{- 8 - 2 14}{2 \cdot 1}

c = \frac{- 8 + 2 14}{2 \cdot 1} : - 4 + 14

c = \frac{- 8 - 2 14}{2 \cdot 1} : - 4 - 14

The solutions to the quadratic equation are:

c = - 4 + 14, c = - 4 - 14

2 x^{2} - 7 x - 15 = 0

2^{\frac{3}{2}} \cdot \frac{2}{3}

4 v^{2} + 7 v = 1

4 x^{2} + 4 x = 11

- 2 h - 1 = - 1 - 2 h

What are the solutions to the equation c^2+8c=-2 ?
The solutions to the equation c^2+8c=-2 are c=-4+sqrt(14),c=-4-sqrt(14)
Find the zeros of c^2+8c=-2
The zeros of c^2+8c=-2 are c=-4+sqrt(14),c=-4-sqrt(14)