What are the solutions to the equation x^2+7x=-12 ?

The solutions to the equation x^2+7x=-12 are x=-3,x=-4

Find the zeros of x^2+7x=-12

The zeros of x^2+7x=-12 are x=-3,x=-4

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x^{2} + 7 x = - 12

x = - 3, x = - 4

Solution steps

x^{2} + 7 x = - 12

Move

12

to the left side

x^{2} + 7 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 1}, x_{2} = \frac{- 7 - 1}{2 \cdot 1}

x = \frac{- 7 + 1}{2 \cdot 1} : - 3

x = \frac{- 7 - 1}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 3, x = - 4

x^{4} - 3 x^{3} + 3 x^{2} - 3 x + 2

(3 x - 5)^{2} + 7 (3 x - 5) + 12 = 0

∣ 8 - 4 x ∣ \leq 3

\frac{- n ^{2} + 16 n - 63}{n ^{2} - 2 n - 35}

\frac{1}{3} \cdot 60

What are the solutions to the equation x^2+7x=-12 ?
The solutions to the equation x^2+7x=-12 are x=-3,x=-4
Find the zeros of x^2+7x=-12
The zeros of x^2+7x=-12 are x=-3,x=-4