What are the solutions to the equation r^2-10r+34=0 ?

The solutions to the equation r^2-10r+34=0 are r=5+3i,r=5-3i

Find the zeros of r^2-10r+34=0

The zeros of r^2-10r+34=0 are r=5+3i,r=5-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} - 10 r + 34 = 0

r = 5 + 3 i, r = 5 - 3 i

Solution steps

r^{2} - 10 r + 34 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 34 : 6 i

r_{1, 2} = \frac{- ( - 10 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 10 ) + 6 i}{2 \cdot 1}, r_{2} = \frac{- ( - 10 ) - 6 i}{2 \cdot 1}

r = \frac{- ( - 10 ) + 6 i}{2 \cdot 1} : 5 + 3 i

r = \frac{- ( - 10 ) - 6 i}{2 \cdot 1} : 5 - 3 i

The solutions to the quadratic equation are:

r = 5 + 3 i, r = 5 - 3 i

3 (y - 5) - 7 (y - 2) = 3

2 (2) - 5

\frac{8 x}{21 y ^{3}} \cdot \frac{7 y ^{2}}{16 x ^{3}}

π \cdot \frac{1}{4}

10 x - 18 y

What are the solutions to the equation r^2-10r+34=0 ?
The solutions to the equation r^2-10r+34=0 are r=5+3i,r=5-3i
Find the zeros of r^2-10r+34=0
The zeros of r^2-10r+34=0 are r=5+3i,r=5-3i