What are the solutions to the equation x^2-6x+6=0 ?

The solutions to the equation x^2-6x+6=0 are x=3+sqrt(3),x=3-sqrt(3)

Find the zeros of x^2-6x+6=0

The zeros of x^2-6x+6=0 are x=3+sqrt(3),x=3-sqrt(3)

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x^{2} - 6 x + 6 = 0

x = 3 + 3, x = 3 - 3

Decimal Notation

x = 4.73205 \dots, x = 1.26794 \dots

Solution steps

x^{2} - 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 6 = 23

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 3}{2 \cdot 1} : 3 + 3

x = \frac{- ( - 6 ) - 2 3}{2 \cdot 1} : 3 - 3

The solutions to the quadratic equation are:

x = 3 + 3, x = 3 - 3

8 x - 21 = 2 x - 9

x - 9 = 12

10 ∣ - 2 n + 4 ∣ - 5 < 15

x^{2} + 9 x

What are the solutions to the equation x^2-6x+6=0 ?
The solutions to the equation x^2-6x+6=0 are x=3+sqrt(3),x=3-sqrt(3)
Find the zeros of x^2-6x+6=0
The zeros of x^2-6x+6=0 are x=3+sqrt(3),x=3-sqrt(3)