What is the answer to (x-3)(x+4)-2(3x-2)=(x-4)^2 ?

The answer to (x-3)(x+4)-2(3x-2)=(x-4)^2 is x=8

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(x-3)(x+4)-2(3x-2)=(x-4)^2

(x - 3) (x + 4) - 2 (3 x - 2) = (x - 4)^{2}

x = 8

Solution steps

(x - 3) (x + 4) - 2 (3 x - 2) = (x - 4)^{2}

Expand

(x - 3) (x + 4) - 2 (3 x - 2) : x^{2} - 5 x - 8

Expand

(x - 4)^{2} : x^{2} - 8 x + 16

x^{2} - 5 x - 8 = x^{2} - 8 x + 16

Move

8

to the right side

x^{2} - 5 x = x^{2} - 8 x + 24

Subtract

x^{2} - 8 x

from both sides

x^{2} - 5 x - (x^{2} - 8 x) = x^{2} - 8 x + 24 - (x^{2} - 8 x)

Simplify

3 x = 24

Divide both sides by

3

x = 8

10 a^{2} b^{2} + 9 a b^{2} - a^{2} b

7 + (5^{3} - \frac{200}{2})

7 m - 7 - 6 m - 16 = 1 + 4 m

- \frac{7 x}{x ^{2} - 100} \geq \frac{x + 2}{x + 10}

(- 2 + 3 i) \cdot (3 - i)

What is the answer to (x-3)(x+4)-2(3x-2)=(x-4)^2 ?
The answer to (x-3)(x+4)-2(3x-2)=(x-4)^2 is x=8
Solve for x: (x-3)(x+4)-2(3x-2)=(x-4)^2
The solution is x=8