What are the solutions to the equation x^2+x+25=0 ?

The solutions to the equation x^2+x+25=0 are x=-1/2+i(3sqrt(11))/2 ,x=-1/2-i(3sqrt(11))/2

Find the zeros of x^2+x+25=0

The zeros of x^2+x+25=0 are x=-1/2+i(3sqrt(11))/2 ,x=-1/2-i(3sqrt(11))/2

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x^{2} + x + 25 = 0

x = - \frac{1}{2} + i \frac{3 11}{2}, x = - \frac{1}{2} - i \frac{3 11}{2}

Solution steps

x^{2} + x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 25 : 311 i

x_{1, 2} = \frac{- 1 \pm 3 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3 11 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 3 11 i}{2 \cdot 1}

x = \frac{- 1 + 3 11 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{3 11}{2}

x = \frac{- 1 - 3 11 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{3 11}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{3 11}{2}, x = - \frac{1}{2} - i \frac{3 11}{2}

1 \times (- 4) - 8 \times \frac{9}{- 3}

49 \cdot 3

4 x^{2} - 3 x + 6 = 0

∣ x - 34 ∣ \leq 3

(x + 9)^{2} = - 45

What are the solutions to the equation x^2+x+25=0 ?
The solutions to the equation x^2+x+25=0 are x=-1/2+i(3sqrt(11))/2 ,x=-1/2-i(3sqrt(11))/2
Find the zeros of x^2+x+25=0
The zeros of x^2+x+25=0 are x=-1/2+i(3sqrt(11))/2 ,x=-1/2-i(3sqrt(11))/2