What are the solutions to the equation (x+4)(x+5)=0 ?

The solutions to the equation (x+4)(x+5)=0 are x=-4,x=-5

Find the zeros of (x+4)(x+5)=0

The zeros of (x+4)(x+5)=0 are x=-4,x=-5

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(x + 4) (x + 5) = 0

x = - 4, x = - 5

Solution steps

(x + 4) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x + 5 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = - 4, x = - 5

(- \frac{5}{4})^{2}

(- \frac{1}{2})^{- 4}

\frac{9}{15 a - 15}

\frac{1}{2} (6) (6)

6 \cdot 18

What are the solutions to the equation (x+4)(x+5)=0 ?
The solutions to the equation (x+4)(x+5)=0 are x=-4,x=-5
Find the zeros of (x+4)(x+5)=0
The zeros of (x+4)(x+5)=0 are x=-4,x=-5