What are the solutions to the equation 3x^2-16x+15=3 ?

The solutions to the equation 3x^2-16x+15=3 are x=(2(4+sqrt(7)))/3 ,x=(2(4-sqrt(7)))/3

Find the zeros of 3x^2-16x+15=3

The zeros of 3x^2-16x+15=3 are x=(2(4+sqrt(7)))/3 ,x=(2(4-sqrt(7)))/3

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3 x^{2} - 16 x + 15 = 3

x = \frac{2 ( 4 + 7 )}{3}, x = \frac{2 ( 4 - 7 )}{3}

Decimal Notation

x = 4.43050 \dots, x = 0.90283 \dots

Solution steps

3 x^{2} - 16 x + 15 = 3

Move

3

to the left side

3 x^{2} - 16 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 \cdot 12 = 47

x_{1, 2} = \frac{- ( - 16 ) \pm 4 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 7}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 4 7}{2 \cdot 3}

x = \frac{- ( - 16 ) + 4 7}{2 \cdot 3} : \frac{2 ( 4 + 7 )}{3}

x = \frac{- ( - 16 ) - 4 7}{2 \cdot 3} : \frac{2 ( 4 - 7 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 4 + 7 )}{3}, x = \frac{2 ( 4 - 7 )}{3}

\frac{6}{3 !}

2 \cdot \frac{\frac{1}{2}}{5} = \frac{p}{4}

x^{2} + 4 x - 12 \geq 0

6 x + 8 y

5 x^{2} + 40 x + 60

What are the solutions to the equation 3x^2-16x+15=3 ?
The solutions to the equation 3x^2-16x+15=3 are x=(2(4+sqrt(7)))/3 ,x=(2(4-sqrt(7)))/3
Find the zeros of 3x^2-16x+15=3
The zeros of 3x^2-16x+15=3 are x=(2(4+sqrt(7)))/3 ,x=(2(4-sqrt(7)))/3