What are the solutions to the equation m^2-m-6=0 ?

The solutions to the equation m^2-m-6=0 are m=3,m=-2

Find the zeros of m^2-m-6=0

The zeros of m^2-m-6=0 are m=3,m=-2

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m^{2} - m - 6 = 0

m = 3, m = - 2

Solution steps

m^{2} - m - 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

m_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

m = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

m = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

m = 3, m = - 2

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What are the solutions to the equation m^2-m-6=0 ?
The solutions to the equation m^2-m-6=0 are m=3,m=-2
Find the zeros of m^2-m-6=0
The zeros of m^2-m-6=0 are m=3,m=-2