What are the solutions to the equation 2k^2=9+3k ?

The solutions to the equation 2k^2=9+3k are k=3,k=-3/2

Find the zeros of 2k^2=9+3k

The zeros of 2k^2=9+3k are k=3,k=-3/2

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2 k^{2} = 9 + 3 k

k = 3, k = - \frac{3}{2}

Decimal Notation

k = 3, k = - 1.5

Solution steps

2 k^{2} = 9 + 3 k

Move

3 k

to the left side

2 k^{2} - 3 k = 9

Move

9

to the left side

2 k^{2} - 3 k - 9 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 9) = 9

k_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 2}, k_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 2}

k = \frac{- ( - 3 ) + 9}{2 \cdot 2} : 3

k = \frac{- ( - 3 ) - 9}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

k = 3, k = - \frac{3}{2}

\frac{1}{3} \cdot \frac{1}{7}

5 t^{2} - 20 + 3 t^{3} - 12 t

\frac{1}{16} x^{2} - x + 4 = 0.9

\frac{8}{15} - \frac{2}{15}

6 x^{2} - 4 x + 2 = 0

What are the solutions to the equation 2k^2=9+3k ?
The solutions to the equation 2k^2=9+3k are k=3,k=-3/2
Find the zeros of 2k^2=9+3k
The zeros of 2k^2=9+3k are k=3,k=-3/2