What are the solutions to the equation 2x^2+3x=-10 ?

The solutions to the equation 2x^2+3x=-10 are x=-3/4+i(sqrt(71))/4 ,x=-3/4-i(sqrt(71))/4

Find the zeros of 2x^2+3x=-10

The zeros of 2x^2+3x=-10 are x=-3/4+i(sqrt(71))/4 ,x=-3/4-i(sqrt(71))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 3 x = - 10

x = - \frac{3}{4} + i \frac{71}{4}, x = - \frac{3}{4} - i \frac{71}{4}

Solution steps

2 x^{2} + 3 x = - 10

Move

10

to the left side

2 x^{2} + 3 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

Simplify

3^{2} - 4 \cdot 2 \cdot 10 : 71 i

x_{1, 2} = \frac{- 3 \pm 71 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 71 i}{2 \cdot 2}, x_{2} = \frac{- 3 - 71 i}{2 \cdot 2}

x = \frac{- 3 + 71 i}{2 \cdot 2} : - \frac{3}{4} + i \frac{71}{4}

x = \frac{- 3 - 71 i}{2 \cdot 2} : - \frac{3}{4} - i \frac{71}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4} + i \frac{71}{4}, x = - \frac{3}{4} - i \frac{71}{4}

8 - 7 x > - 5

x^{3} \cdot x^{6}

x - 7 > - 13

- 9.3 = d - 3.4

What are the solutions to the equation 2x^2+3x=-10 ?
The solutions to the equation 2x^2+3x=-10 are x=-3/4+i(sqrt(71))/4 ,x=-3/4-i(sqrt(71))/4
Find the zeros of 2x^2+3x=-10
The zeros of 2x^2+3x=-10 are x=-3/4+i(sqrt(71))/4 ,x=-3/4-i(sqrt(71))/4