What are the solutions to the equation 19w^2-30w+8=-6w^2 ?

The solutions to the equation 19w^2-30w+8=-6w^2 are w= 4/5 ,w= 2/5

Find the zeros of 19w^2-30w+8=-6w^2

The zeros of 19w^2-30w+8=-6w^2 are w= 4/5 ,w= 2/5

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19 w^{2} - 30 w + 8 = - 6 w^{2}

w = \frac{4}{5}, w = \frac{2}{5}

Decimal Notation

w = 0.8, w = 0.4

Solution steps

19 w^{2} - 30 w + 8 = - 6 w^{2}

Move

6 w^{2}

to the left side

25 w^{2} - 30 w + 8 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 25 \cdot 8}{2 \cdot 25}

(- 30)^{2} - 4 \cdot 25 \cdot 8 = 10

w_{1, 2} = \frac{- ( - 30 ) \pm 10}{2 \cdot 25}

Separate the solutions

w_{1} = \frac{- ( - 30 ) + 10}{2 \cdot 25}, w_{2} = \frac{- ( - 30 ) - 10}{2 \cdot 25}

w = \frac{- ( - 30 ) + 10}{2 \cdot 25} : \frac{4}{5}

w = \frac{- ( - 30 ) - 10}{2 \cdot 25} : \frac{2}{5}

The solutions to the quadratic equation are:

w = \frac{4}{5}, w = \frac{2}{5}

\frac{2 π}{\frac{5 π}{2}}

\frac{x + 3}{x - 2} < 0

35 a^{2} b^{2} - 5 ab

- 50 \leq - 2 x - 10

\frac{1}{5} \leq \frac{1 - 5 t}{8} < \frac{5}{8}

What are the solutions to the equation 19w^2-30w+8=-6w^2 ?
The solutions to the equation 19w^2-30w+8=-6w^2 are w= 4/5 ,w= 2/5
Find the zeros of 19w^2-30w+8=-6w^2
The zeros of 19w^2-30w+8=-6w^2 are w= 4/5 ,w= 2/5