What are the solutions to the equation 2x^2+12x=-18 ?

The solutions to the equation 2x^2+12x=-18 are x=-3

Find the zeros of 2x^2+12x=-18

The zeros of 2x^2+12x=-18 are x=-3

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2 x^{2} + 12 x = - 18

x = - 3

Solution steps

2 x^{2} + 12 x = - 18

Move

18

to the left side

2 x^{2} + 12 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 18}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 \cdot 18 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 2}

x = \frac{- 12}{2 \cdot 2}

\frac{- 12}{2 \cdot 2} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

4 - 8 i

3 x + 0 = 6

- 5 x - 7 < - 3 x + 9 \leq - 5 x + 5

x^{2} - 6 x - 27

What are the solutions to the equation 2x^2+12x=-18 ?
The solutions to the equation 2x^2+12x=-18 are x=-3
Find the zeros of 2x^2+12x=-18
The zeros of 2x^2+12x=-18 are x=-3