What are the solutions to the equation 6x^2+7x-2=0 ?

The solutions to the equation 6x^2+7x-2=0 are x=(-7+sqrt(97))/(12),x=(-7-sqrt(97))/(12)

Find the zeros of 6x^2+7x-2=0

The zeros of 6x^2+7x-2=0 are x=(-7+sqrt(97))/(12),x=(-7-sqrt(97))/(12)

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6 x^{2} + 7 x - 2 = 0

x = \frac{- 7 + 97}{12}, x = \frac{- 7 - 97}{12}

Decimal Notation

x = 0.23740 \dots, x = - 1.40407 \dots

Solution steps

6 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

7^{2} - 4 \cdot 6 (- 2) = 97

x_{1, 2} = \frac{- 7 \pm 97}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 97}{2 \cdot 6}, x_{2} = \frac{- 7 - 97}{2 \cdot 6}

x = \frac{- 7 + 97}{2 \cdot 6} : \frac{- 7 + 97}{12}

x = \frac{- 7 - 97}{2 \cdot 6} : \frac{- 7 - 97}{12}

The solutions to the quadratic equation are:

x = \frac{- 7 + 97}{12}, x = \frac{- 7 - 97}{12}

3 b^{4} - 6 b^{2} + 27 b

\frac{2 n !}{2 ^{n} n !}

3 x^{2} - 4 x - 8 = 0

8 (2 y + 5) = 9 y + 12

ln (\frac{x y}{z})

What are the solutions to the equation 6x^2+7x-2=0 ?
The solutions to the equation 6x^2+7x-2=0 are x=(-7+sqrt(97))/(12),x=(-7-sqrt(97))/(12)
Find the zeros of 6x^2+7x-2=0
The zeros of 6x^2+7x-2=0 are x=(-7+sqrt(97))/(12),x=(-7-sqrt(97))/(12)