What is (36x^{-4}y^2z^0)/(5x^2y^{-3)z^{-2}} ?

The solution to (36x^{-4}y^2z^0)/(5x^2y^{-3)z^{-2}} is (36y^5z^2)/(5x^6)

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simplify (36x^{-4}y^2z^0)/(5x^2y^{-3)z^{-2}}

simplify

\frac{36 x ^{- 4} y ^{2} z ^{0}}{5 x ^{2} y ^{- 3} z ^{- 2}}

\frac{36 y ^{5} z ^{2}}{5 x ^{6}}

Solution steps

\frac{36 x ^{- 4} y ^{2} z ^{0}}{5 x ^{2} y ^{- 3} z ^{- 2}}

Simplify

\frac{36 x ^{- 4} y ^{2} z ^{0}}{5 x ^{2} y ^{- 3} z ^{- 2}} : \frac{36 x ^{- 4} y ^{2}}{5 x ^{2} y ^{- 3} z ^{- 2}}

= \frac{36 x ^{- 4} y ^{2}}{5 x ^{2} y ^{- 3} z ^{- 2}}

Simplify

\frac{y ^{2}}{y ^{- 3}} : y^{5}

= \frac{36 x ^{- 4} y ^{5}}{5 x ^{2} z ^{- 2}}

Simplify

\frac{x ^{- 4}}{x ^{2}} : \frac{1}{x ^{6}}

= \frac{36 y ^{5}}{5 x ^{6} z ^{- 2}}

Simplify

\frac{36 y ^{5}}{5 x ^{6} z ^{- 2}} : \frac{36 y ^{5} z ^{2}}{5 x ^{6}}

= \frac{36 y ^{5} z ^{2}}{5 x ^{6}}

- 0.8 \cdot ln ∣ 1 - x ∣ = 8

7 ∣ 2 x - 1 ∣ = 21

\frac{5 y - 6}{2} = y - \frac{2 - y}{3}

5 (x + 3) \leq 0

25 - x^{2} < 0

What is (36x^{-4}y^2z^0)/(5x^2y^{-3)z^{-2}} ?
The solution to (36x^{-4}y^2z^0)/(5x^2y^{-3)z^{-2}} is (36y^5z^2)/(5x^6)