What are the solutions to the equation r^2+0.2r+0.01=0 ?

The solutions to the equation r^2+0.2r+0.01=0 are r=-1/10

Find the zeros of r^2+0.2r+0.01=0

The zeros of r^2+0.2r+0.01=0 are r=-1/10

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r^{2} + 0.2 r + 0.01 = 0

r = - \frac{1}{10}

Decimal Notation

r = - 0.1

Solution steps

r^{2} + 0.2 r + 0.01 = 0

Multiply both sides by

100

100 r^{2} + 20 r + 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 100 \cdot 1}{2 \cdot 100}

2 0^{2} - 4 \cdot 100 \cdot 1 = 0

r_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 100}

r = \frac{- 20}{2 \cdot 100}

\frac{- 20}{2 \cdot 100} = - \frac{1}{10}

r = - \frac{1}{10}

The solution to the quadratic equation is:

r = - \frac{1}{10}

2 y - 3 > 9

0.7 = \frac{3}{4} y^{2} - \frac{41}{4} y + \frac{139}{4}

x^{4} - 2 x^{2} \geq 8

2 x^{2} + 16 x - 40

(- 5 n^{4} + 8) + (5 n^{4} + 8 n^{3} + 3 n^{2})

What are the solutions to the equation r^2+0.2r+0.01=0 ?
The solutions to the equation r^2+0.2r+0.01=0 are r=-1/10
Find the zeros of r^2+0.2r+0.01=0
The zeros of r^2+0.2r+0.01=0 are r=-1/10