What are the solutions to the equation 2x^2+7x+2=0 ?

The solutions to the equation 2x^2+7x+2=0 are x=(-7+sqrt(33))/4 ,x=(-7-sqrt(33))/4

Find the zeros of 2x^2+7x+2=0

The zeros of 2x^2+7x+2=0 are x=(-7+sqrt(33))/4 ,x=(-7-sqrt(33))/4

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2 x^{2} + 7 x + 2 = 0

x = \frac{- 7 + 33}{4}, x = \frac{- 7 - 33}{4}

Decimal Notation

x = - 0.31385 \dots, x = - 3.18614 \dots

Solution steps

2 x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

7^{2} - 4 \cdot 2 \cdot 2 = 33

x_{1, 2} = \frac{- 7 \pm 33}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 33}{2 \cdot 2}, x_{2} = \frac{- 7 - 33}{2 \cdot 2}

x = \frac{- 7 + 33}{2 \cdot 2} : \frac{- 7 + 33}{4}

x = \frac{- 7 - 33}{2 \cdot 2} : \frac{- 7 - 33}{4}

The solutions to the quadratic equation are:

x = \frac{- 7 + 33}{4}, x = \frac{- 7 - 33}{4}

4 x^{2} - 4 x + 1

5 x^{2} - 28 x - 12

\frac{4 ^{3}}{3}

3 m^{2} - mn - 2 n^{2}

x^{2} + 9 x + 2 \geq - 16

What are the solutions to the equation 2x^2+7x+2=0 ?
The solutions to the equation 2x^2+7x+2=0 are x=(-7+sqrt(33))/4 ,x=(-7-sqrt(33))/4
Find the zeros of 2x^2+7x+2=0
The zeros of 2x^2+7x+2=0 are x=(-7+sqrt(33))/4 ,x=(-7-sqrt(33))/4