What are the solutions to the equation -x^2+14x=48 ?

The solutions to the equation -x^2+14x=48 are x=6,x=8

Find the zeros of -x^2+14x=48

The zeros of -x^2+14x=48 are x=6,x=8

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- x^{2} + 14 x = 48

x = 6, x = 8

Solution steps

- x^{2} + 14 x = 48

Move

48

to the left side

- x^{2} + 14 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 1 ) ( - 48 )}{2 ( - 1 )}

1 4^{2} - 4 (- 1) (- 48) = 2

x_{1, 2} = \frac{- 14 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 14 + 2}{2 ( - 1 )}, x_{2} = \frac{- 14 - 2}{2 ( - 1 )}

x = \frac{- 14 + 2}{2 ( - 1 )} : 6

x = \frac{- 14 - 2}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = 6, x = 8

(a^{\frac{1}{2}} \cdot b^{\frac{1}{3}})^{\frac{1}{2}}

2 x - 7 = - 3 x + 18

x^{3} - 8 y^{3}

2 x + 4

x^{2} - 2 x + 1 = - x^{2} + 4 x - 3

What are the solutions to the equation -x^2+14x=48 ?
The solutions to the equation -x^2+14x=48 are x=6,x=8
Find the zeros of -x^2+14x=48
The zeros of -x^2+14x=48 are x=6,x=8