What is factor (x+1)^2-4y^2 ?

The solution to factor (x+1)^2-4y^2 is (x+1+2y)(x+1-2y)

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factor (x+1)^2-4y^2

factor

(x + 1)^{2} - 4 y^{2}

(x + 1 + 2 y) (x + 1 - 2 y)

Solution steps

(x + 1)^{2} - 4 y^{2}

Simplify

4 y^{2} : (2 y)^{2}

= (x + 1)^{2} - (2 y)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x + 1)^{2} - (2 y)^{2} = ((x + 1) + 2 y) ((x + 1) - 2 y)

= ((x + 1) + 2 y) ((x + 1) - 2 y)

Apply rule:

(a) = a

(x + 1) = x + 1

= (x + 1 + 2 y) (x + 1 - 2 y)

5 x^{2} - 44 x - 9

x^{2} + 10 x < 0

4 x + 1 \geq 2 x + 3

\frac{x ^{2} + x - 2}{x ^{2} - 1}

((\frac{3}{5})^{4} \cdot (\frac{3}{5})^{- 3} + 1)^{- \frac{1}{3}}

What is factor (x+1)^2-4y^2 ?
The solution to factor (x+1)^2-4y^2 is (x+1+2y)(x+1-2y)