What is 3x^2-7x^2+2>= 0 ?

The solution to 3x^2-7x^2+2>= 0 is -sqrt(1/2)<= x<= sqrt(1/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^2-7x^2+2>= 0

3 x^{2} - 7 x^{2} + 2 \geq 0

- \frac{1}{2} \leq x \leq \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \frac{1}{2}]

Decimal Notation

- 0.70710 \dots \leq x \leq 0.70710 \dots

Solution steps

3 x^{2} - 7 x^{2} + 2 \geq 0

Simplify

- 4 x^{2} + 2 \geq 0

Move

2

to the right side

- 4 x^{2} \geq - 2

Multiply both sides by

- 1

4 x^{2} \leq 2

Divide both sides by

4

x^{2} \leq \frac{1}{2}

For

u^{n} \leq a

, if

n

is even then

- \frac{1}{2} \leq x \leq \frac{1}{2}

x - 1 < 1

- 3 = \frac{x}{2} - 5

(4 x - 2) 2 = 17

u^{2} = 49

15 x^{8} + 30 x^{5} - 45 x^{4}

What is 3x^2-7x^2+2>= 0 ?
The solution to 3x^2-7x^2+2>= 0 is -sqrt(1/2)<= x<= sqrt(1/2)