What are the solutions to the equation t^2+5t+6=0 ?

The solutions to the equation t^2+5t+6=0 are t=-2,t=-3

Find the zeros of t^2+5t+6=0

The zeros of t^2+5t+6=0 are t=-2,t=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t^{2} + 5 t + 6 = 0

t = - 2, t = - 3

Solution steps

t^{2} + 5 t + 6 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

t_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 5 + 1}{2 \cdot 1}, t_{2} = \frac{- 5 - 1}{2 \cdot 1}

t = \frac{- 5 + 1}{2 \cdot 1} : - 2

t = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

t = - 2, t = - 3

4 y^{2} - 28 y + 49

x^{3} - 9 x^{2} + 18 x

8 x - 14 \leq 5 x - 15

(x - 5)^{2} = 9

- 1 \leq 2 x + 5 and 2 x + 3 < 11

What are the solutions to the equation t^2+5t+6=0 ?
The solutions to the equation t^2+5t+6=0 are t=-2,t=-3
Find the zeros of t^2+5t+6=0
The zeros of t^2+5t+6=0 are t=-2,t=-3