What are the solutions to the equation 3x^2-2x-4=0 ?

The solutions to the equation 3x^2-2x-4=0 are x=(1+sqrt(13))/3 ,x=(1-sqrt(13))/3

Find the zeros of 3x^2-2x-4=0

The zeros of 3x^2-2x-4=0 are x=(1+sqrt(13))/3 ,x=(1-sqrt(13))/3

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3 x^{2} - 2 x - 4 = 0

x = \frac{1 + 13}{3}, x = \frac{1 - 13}{3}

Solution steps

3 x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 4) = 213

x_{1, 2} = \frac{- ( - 2 ) \pm 2 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 13}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 13}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 13}{2 \cdot 3} : \frac{1 + 13}{3}

x = \frac{- ( - 2 ) - 2 13}{2 \cdot 3} : \frac{1 - 13}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 13}{3}, x = \frac{1 - 13}{3}

\frac{2}{3} + 5

8 x^{\frac{7}{3}} + 24 x^{\frac{4}{3}} + 18 x^{\frac{1}{3}}

- 0.1 x^{2} + 90 x = 20250

x^{2} - 23 x - 50

4 x^{2} = 13 x - 75

What are the solutions to the equation 3x^2-2x-4=0 ?
The solutions to the equation 3x^2-2x-4=0 are x=(1+sqrt(13))/3 ,x=(1-sqrt(13))/3
Find the zeros of 3x^2-2x-4=0
The zeros of 3x^2-2x-4=0 are x=(1+sqrt(13))/3 ,x=(1-sqrt(13))/3