What are the solutions to the equation (x+3)(x+8)=0 ?

The solutions to the equation (x+3)(x+8)=0 are x=-3,x=-8

Find the zeros of (x+3)(x+8)=0

The zeros of (x+3)(x+8)=0 are x=-3,x=-8

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(x + 3) (x + 8) = 0

x = - 3, x = - 8

Solution steps

(x + 3) (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x + 8 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 8 = 0 : x = - 8

The solutions to the quadratic equation are:

x = - 3, x = - 8

3108

3 x^{4} y^{2} - 9 x^{2} y^{2}

14 x^{3} \cdot x^{\frac{1}{2}}

∣ 3 x - 3 ∣ < 12

(x + 8) (x + 2) (x - 3) \geq 0

What are the solutions to the equation (x+3)(x+8)=0 ?
The solutions to the equation (x+3)(x+8)=0 are x=-3,x=-8
Find the zeros of (x+3)(x+8)=0
The zeros of (x+3)(x+8)=0 are x=-3,x=-8