What are the solutions to the equation 0=3x^2-9 ?

The solutions to the equation 0=3x^2-9 are x=sqrt(3),x=-sqrt(3)

Find the zeros of 0=3x^2-9

The zeros of 0=3x^2-9 are x=sqrt(3),x=-sqrt(3)

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0 = 3 x^{2} - 9

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

0 = 3 x^{2} - 9

Switch sides

3 x^{2} - 9 = 0

Move

9

to the right side

3 x^{2} = 9

Divide both sides by

3

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

\frac{1}{8} - \frac{1}{5} + \frac{1}{12}

x^{2} - 36 \geq 1

\frac{x}{3} > 1

- 4 (x + 1) \leq x + 6

\frac{π}{8} + \frac{3 π}{8}

What are the solutions to the equation 0=3x^2-9 ?
The solutions to the equation 0=3x^2-9 are x=sqrt(3),x=-sqrt(3)
Find the zeros of 0=3x^2-9
The zeros of 0=3x^2-9 are x=sqrt(3),x=-sqrt(3)