What are the solutions to the equation 4x^2+8x=-4 ?

The solutions to the equation 4x^2+8x=-4 are x=-1

Find the zeros of 4x^2+8x=-4

The zeros of 4x^2+8x=-4 are x=-1

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4 x^{2} + 8 x = - 4

x = - 1

Solution steps

4 x^{2} + 8 x = - 4

Move

4

to the left side

4 x^{2} + 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 4 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 4}

x = \frac{- 8}{2 \cdot 4}

\frac{- 8}{2 \cdot 4} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

\frac{x ^{- 4} y ^{- 5} y ^{2}}{x}

(- 2)^{- 2}

\frac{7 - x}{x - 5} \geq - 3

- 2.4 (2) + 9.6

(- \frac{1}{2} x)^{2}

What are the solutions to the equation 4x^2+8x=-4 ?
The solutions to the equation 4x^2+8x=-4 are x=-1
Find the zeros of 4x^2+8x=-4
The zeros of 4x^2+8x=-4 are x=-1