What are the solutions to the equation 10x^2-19x-15=0 ?

The solutions to the equation 10x^2-19x-15=0 are x= 5/2 ,x=-3/5

Find the zeros of 10x^2-19x-15=0

The zeros of 10x^2-19x-15=0 are x= 5/2 ,x=-3/5

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10 x^{2} - 19 x - 15 = 0

x = \frac{5}{2}, x = - \frac{3}{5}

Decimal Notation

x = 2.5, x = - 0.6

Solution steps

10 x^{2} - 19 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 10 ( - 15 )}{2 \cdot 10}

(- 19)^{2} - 4 \cdot 10 (- 15) = 31

x_{1, 2} = \frac{- ( - 19 ) \pm 31}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 31}{2 \cdot 10}, x_{2} = \frac{- ( - 19 ) - 31}{2 \cdot 10}

x = \frac{- ( - 19 ) + 31}{2 \cdot 10} : \frac{5}{2}

x = \frac{- ( - 19 ) - 31}{2 \cdot 10} : - \frac{3}{5}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{3}{5}

9 r^{2} + 30 r + 25 = 0

3 x^{2} + 5 x + 2

2 x^{3} + x^{2} + 8 x + 4

\frac{1}{10 \cdot 1 0 ^{- 6}}

105 ab - 90 a - 21 b + 18

What are the solutions to the equation 10x^2-19x-15=0 ?
The solutions to the equation 10x^2-19x-15=0 are x= 5/2 ,x=-3/5
Find the zeros of 10x^2-19x-15=0
The zeros of 10x^2-19x-15=0 are x= 5/2 ,x=-3/5