What are the solutions to the equation 14x^2-28=0 ?

The solutions to the equation 14x^2-28=0 are x=sqrt(2),x=-sqrt(2)

Find the zeros of 14x^2-28=0

The zeros of 14x^2-28=0 are x=sqrt(2),x=-sqrt(2)

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14 x^{2} - 28 = 0

x = 2, x = - 2

Solution steps

14 x^{2} - 28 = 0

Move

28

to the right side

14 x^{2} = 28

Divide both sides by

14

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

- 5 m^{2} - 15 m + 50

8 k^{2} - 18

20 \leq \frac{m}{5} + 12

\frac{( x - 2 )}{12} - \frac{( x + 1 )}{12} = \frac{( 4 x - 3 )}{12}

\frac{4}{6} + \frac{1}{6}

What are the solutions to the equation 14x^2-28=0 ?
The solutions to the equation 14x^2-28=0 are x=sqrt(2),x=-sqrt(2)
Find the zeros of 14x^2-28=0
The zeros of 14x^2-28=0 are x=sqrt(2),x=-sqrt(2)