What are the solutions to the equation 3(x+3)^2=27 ?

The solutions to the equation 3(x+3)^2=27 are x=0,x=-6

Find the zeros of 3(x+3)^2=27

The zeros of 3(x+3)^2=27 are x=0,x=-6

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3 (x + 3)^{2} = 27

x = 0, x = - 6

Solution steps

3 (x + 3)^{2} = 27

Divide both sides by

3

(x + 3)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 9 : x = 0

Solve

x + 3 = - 9 : x = - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

\frac{2 t x}{t ^{2} - x ^{2}}

\frac{n ^{4}}{5 n ^{- 2}}

6 + (- 6)

- (\frac{- 1}{4})

4 y^{2} + 35 y + 66

What are the solutions to the equation 3(x+3)^2=27 ?
The solutions to the equation 3(x+3)^2=27 are x=0,x=-6
Find the zeros of 3(x+3)^2=27
The zeros of 3(x+3)^2=27 are x=0,x=-6