What is ((3x^5y^4)/(x^0y^{-3)})^2 ?

The solution to ((3x^5y^4)/(x^0y^{-3)})^2 is 9x^{10}y^{14}

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simplify ((3x^5y^4)/(x^0y^{-3)})^2

simplify

(\frac{3 x ^{5} y ^{4}}{x ^{0} y ^{- 3}})^{2}

9 x^{10} y^{14}

Solution steps

(\frac{3 x ^{5} y ^{4}}{x ^{0} y ^{- 3}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 x ^{5} y ^{4} ) ^{2}}{( x ^{0} y ^{- 3} ) ^{2}}

Simplify

(3 x^{5} y^{4})^{2} : 9 x^{10} y^{8}

= \frac{9 x ^{10} y ^{8}}{( x ^{0} y ^{- 3} ) ^{2}}

Simplify

(x^{0} y^{- 3})^{2} : \frac{1}{y ^{6}}

= \frac{9 x ^{10} y ^{8}}{\frac{1}{y ^{6}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{9 x ^{10} y ^{8} y ^{6}}{1}

Apply rule

\frac{a}{1} = a

= 9 x^{10} y^{8} y^{6}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{8} y^{6} = y^{8 + 6}

= 9 x^{10} y^{8 + 6}

Add the numbers:

8 + 6 = 14

= 9 x^{10} y^{14}

(2 - x)^{2} \leq 3

x^{2} + 12 x = 28

7 h^{4} - 7 p^{4}

3 x^{2} - 5 x = 4

What is ((3x^5y^4)/(x^0y^{-3)})^2 ?
The solution to ((3x^5y^4)/(x^0y^{-3)})^2 is 9x^{10}y^{14}