What is (2x-1)-4(5x-2)<= 9-(6x-3) ?

The solution to (2x-1)-4(5x-2) =-5/12

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(2x-1)-4(5x-2)<= 9-(6x-3)

(2 x - 1) - 4 (5 x - 2) \leq 9 - (6 x - 3)

x \geq - \frac{5}{12}

Interval Notation

[- \frac{5}{12}, \infty)

Decimal Notation

x \geq - 0.41666 \dots

Solution steps

(2 x - 1) - 4 (5 x - 2) \leq 9 - (6 x - 3)

2 x - 1 - 4 (5 x - 2) \leq 9 - (6 x - 3)

Expand

2 x - 1 - 4 (5 x - 2) : - 18 x + 7

Expand

9 - (6 x - 3) : - 6 x + 12

- 18 x + 7 \leq - 6 x + 12

Move

7

to the right side

- 18 x \leq - 6 x + 5

Move

6 x

to the left side

- 12 x \leq 5

Multiply both sides by

- 1

12 x \geq - 5

Divide both sides by

12

x \geq - \frac{5}{12}

t^{2} + 12 t + 36

86 \cdot \frac{π}{180}

\frac{1}{\frac{9}{4}}

\frac{3 - 4 x}{5} - \frac{2 x + 5}{3} = \frac{x - 10}{2}

7 x^{2} + 11 x - 6

What is (2x-1)-4(5x-2)<= 9-(6x-3) ?
The solution to (2x-1)-4(5x-2)<= 9-(6x-3) is x>=-5/12