What are the solutions to the equation 24^2+7^2=c^2 ?

The solutions to the equation 24^2+7^2=c^2 are c=25,c=-25

Find the zeros of 24^2+7^2=c^2

The zeros of 24^2+7^2=c^2 are c=25,c=-25

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2 4^{2} + 7^{2} = c^{2}

c = 25, c = - 25

Solution steps

2 4^{2} + 7^{2} = c^{2}

Switch sides

c^{2} = 2 4^{2} + 7^{2}

Simplify

2 4^{2} + 7^{2} : 625

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 625, c = - 625

625 = 25

- 625 = - 25

c = 25, c = - 25

32 m^{2} + 28 m - 49

(1 - 82) (1 + 82)

\frac{16}{25}

\frac{3 x + 5}{2} = - 5

\frac{y ^{2}}{y ^{7}}

What are the solutions to the equation 24^2+7^2=c^2 ?
The solutions to the equation 24^2+7^2=c^2 are c=25,c=-25
Find the zeros of 24^2+7^2=c^2
The zeros of 24^2+7^2=c^2 are c=25,c=-25