What are the solutions to the equation x^2-8x+97=0 ?

The solutions to the equation x^2-8x+97=0 are x=4+9i,x=4-9i

Find the zeros of x^2-8x+97=0

The zeros of x^2-8x+97=0 are x=4+9i,x=4-9i

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x^{2} - 8 x + 97 = 0

x = 4 + 9 i, x = 4 - 9 i

Solution steps

x^{2} - 8 x + 97 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 97}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 97 : 18 i

x_{1, 2} = \frac{- ( - 8 ) \pm 18 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 18 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 18 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 18 i}{2 \cdot 1} : 4 + 9 i

x = \frac{- ( - 8 ) - 18 i}{2 \cdot 1} : 4 - 9 i

The solutions to the quadratic equation are:

x = 4 + 9 i, x = 4 - 9 i

\frac{x}{9} - 2 > - 1

∣ 2 z + 7 ∣ = ∣ z + 6 ∣

∣ y ∣ - 2 \leq 0

\frac{5}{6} k - 5 = 10

0 = 2 x^{2} - 1

What are the solutions to the equation x^2-8x+97=0 ?
The solutions to the equation x^2-8x+97=0 are x=4+9i,x=4-9i
Find the zeros of x^2-8x+97=0
The zeros of x^2-8x+97=0 are x=4+9i,x=4-9i