What are the solutions to the equation x^2-5x+8=0 ?

The solutions to the equation x^2-5x+8=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2

Find the zeros of x^2-5x+8=0

The zeros of x^2-5x+8=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2

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x^{2} - 5 x + 8 = 0

x = \frac{5}{2} + i \frac{7}{2}, x = \frac{5}{2} - i \frac{7}{2}

Solution steps

x^{2} - 5 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 8 : 7 i

x_{1, 2} = \frac{- ( - 5 ) \pm 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7 i}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 7 i}{2 \cdot 1}

x = \frac{- ( - 5 ) + 7 i}{2 \cdot 1} : \frac{5}{2} + i \frac{7}{2}

x = \frac{- ( - 5 ) - 7 i}{2 \cdot 1} : \frac{5}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{7}{2}, x = \frac{5}{2} - i \frac{7}{2}

\frac{( e ^{x - 1} )}{1.5} < 1

w^{2} = 3 (w - 1)

\frac{2 7 ^{\frac{4}{3}}}{2 7 ^{\frac{2}{3}}}

16 x^{2} - 9 = 0

4 x^{3} + 24 x^{2} + 32 x

What are the solutions to the equation x^2-5x+8=0 ?
The solutions to the equation x^2-5x+8=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2
Find the zeros of x^2-5x+8=0
The zeros of x^2-5x+8=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2